3x+[3x-2(x-2y)-3x]=

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Solution for 3x+[3x-2(x-2y)-3x]= equation:


Simplifying
3x + [3x + -2(x + -2y) + -3x] = 0
3x + [3x + (x * -2 + -2y * -2) + -3x] = 0
3x + [3x + (-2x + 4y) + -3x] = 0

Reorder the terms:
3x + [3x + -2x + -3x + 4y] = 0

Combine like terms: 3x + -2x = 1x
3x + [1x + -3x + 4y] = 0

Combine like terms: 1x + -3x = -2x
3x + [-2x + 4y] = 0

Remove brackets around [-2x + 4y]
3x + -2x + 4y = 0

Combine like terms: 3x + -2x = 1x
1x + 4y = 0

Solving
1x + 4y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y' to each side of the equation.
1x + 4y + -4y = 0 + -4y

Combine like terms: 4y + -4y = 0
1x + 0 = 0 + -4y
1x = 0 + -4y
Remove the zero:
1x = -4y

Divide each side by '1'.
x = -4y

Simplifying
x = -4y

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